本文共 1709 字,大约阅读时间需要 5 分钟。
Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 5437 | Accepted: 3845 |
Description
The nth Triangular number, T(n) = 1 + … + n, is the sum of the first n integers. It is the number of points in a triangular array with n points on side. For example T(4):
XX XX X XX X X X
Write a program to compute the weighted sum of triangular numbers:
W(n) = SUM[k = 1…n; k * T(k + 1)]
Input
The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.
Each dataset consists of a single line of input containing a single integer n, (1 ≤ n ≤300), which is the number of points on a side of the triangle.
Output
For each dataset, output on a single line the dataset number (1 through N), a blank, the value of n for the dataset, a blank, and the weighted sum ,W(n), of triangular numbers for n.
Sample Input
434510
Sample Output
1 3 452 4 1053 5 2104 10 2145
Source
#include#include #include int T[310];int W[310];void init(){ int i, j; memset(W, 0, sizeof(W)); T[1] = 1; for (i = 2; i <= 304; i++){ T[i] = T[i - 1] + i; } W[1] = T[2]; for (i = 2; i<= 303; i++){ W[i] = W[i - 1] + i * T[i + 1]; }}int main(void){ int ii, casenum; int n; init(); scanf("%d", &casenum); for (ii = 1; ii <= casenum; ii++){ scanf("%d", &n); printf("%d %d %d\n", ii, n, W[n]); } return 0;}
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